if I have two nsdatecomponent and I want a know if the TIME in the first object is bigger than the second.
example:
if (nsdatecomponentObject1 > nsdatecomponentObject2)
{
//something
}
Because this way don't works, how I can do this?
在NSDateComponent
的NSDate
上使用compare:
NSDateComponent
if([[nsdatecomponentObject1 date] compare:[nsdatecomponentObject2 date]] == NSOrderedAscending)
The right (and only) way to compare "on-the-fly" two NSDateComponents, is to use an NSCalendar object:
NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
switch([[gregorian dateFromComponents:oneNSDateComponents] compare:[gregorian dateFromComponents:anotherNSDateComponents]]) {
case NSOrderedSame:
NSLog(@"orderSame");
break;
case NSOrderedAscending:
NSLog(@"orderAscending");
break;
case NSOrderedDescending:
NSLog(@"orderDescending");
break;
}
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