printf UTF8 characters with printf from Hexadecimal ints

Question

Kind of trivial thing but ... I want to print japanese characters using plain C from Hexadecimals

From this table , I know that, the first char in the table, あ's Entity is &# 12353 and its Hex Entity is x3041, etc.

But how do I use this two numbers in order to get printed all characters in the command line?

Answer 1

If your terminal is set to UTF-8 and locale is set correctly, you may write:

char s[]="あ";

you can also try

 char s[]={0xe3,0x81,0x82,0x0}

(the last is the Unicode UTF-8 encoding for "あ"), and then just printf("%s",s);

Answer 2

如果定义了__STDC_ISO_10646__ ，则wchar_t采用Unicode，您可以执行以下操作：

printf("%lc", (wchar_t)0x3041);