PowerShell: How to source a function like source a file?

Question

In my main script, I will first call an init function to initiate many variables which I expected to be used in the script. One way is to use variables whose name are like $script:var1 which are script level variable. But that's kind of ugly and I'd like to use normal variable name, so I need a mechanism to source a function just like source a file.

When source a file, all the variables in that file are available in the calling script.

Answer 1

使用与使用dot-operator相同的语法，就像获取文件一样：

. My-Function

Answer 2

You can also do it in a scriptblock and dot-source that, but the rules are slightly different. You must have a space after the period to dot-source a function, and you don't with a scriptblock.

Both of these will produce 42

$a=0
function init {$a=42}
. init
$a

$a=0 
$init={$a=42}
.$init
$a