S -> bA|aB
A -> a|aS|bAA
B -> b|bS|aBB
Any easy method other than trying to find a string that would generate two parse trees ?
Can someone please give me a string that can prove this.
There is a string though: bbaaba
S -> bA -> bbAA -> bbaA -> bbaaS -> bbaabA -> bbaaba
S -> bA -> bbAA -> bbaSA -> bbaaBA -> bbaabA -> bbaaba
没有简单的方法来证明无上下文语法模糊不清 - 实际上,通过简化Post对应问题 , 这个问题是不可判定的 。
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