I've 2 models Worker
and Position
when I add a new worker there should be selectbox with the positions listed in Positions
model.
I tried to use Select
widget but django fails with no such property
exception.
Models
# Position model
class Position(models.Model):
p_name = models.CharField(max_length = 40, unique = True, verbose_name = 'Position')
p_salary = models.IntegerField(max_length = 11, verbose_name = 'Salary')
fields = ('p_name', 'p_salary')
# Worker model
class Worker(models.Model):
w_name = models.CharField(max_length = 40, verbose_name = 'Name')
w_lastname = models.CharField(max_length = 40, verbose_name = 'Lastname')
w_position = models.ForeignKey(to = Position, to_field = 'p_name', verbose_name = 'Position')
w_dept = models.ForeignKey(to = Department, to_field = 'd_name' verbose_name = 'Department')
Form
class WorkerForm(ModelForm):
class Meta:
model = Worker
widgets = {
'w_name' : TextInput(attrs = {'class': 'e name'}),
'w_lastame' : TextInput(attrs = {'class': 'e lastname'}),
'w_position': Select(attrs = {'class': 'e position'}),
'w_dept' : Select(attrs = {'class': 'e department'}),
}
Definition in admin.py
class WorkerAdmin(admin.ModelAdmin):
form = WorkerForm
list_display = ('w_name', 'w_lastname', 'w_position', 'w_dept')
What goes wrong how to make select box appear according to a foreign key?
Sultan
您可以尝试在表单内重新声明表单的字段(确保使用与Model中相同的名称),然后在其中设置小部件和属性?
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