[英]Django: model foreign key and a selectbox widget
我有2个模型Worker
和Position
当我添加一个新worker时,应该有selectbox,其位置在Positions
模型中列出。
我尝试使用“ Select
小部件,但django失败, no such property
异常。
楷模
# Position model
class Position(models.Model):
p_name = models.CharField(max_length = 40, unique = True, verbose_name = 'Position')
p_salary = models.IntegerField(max_length = 11, verbose_name = 'Salary')
fields = ('p_name', 'p_salary')
# Worker model
class Worker(models.Model):
w_name = models.CharField(max_length = 40, verbose_name = 'Name')
w_lastname = models.CharField(max_length = 40, verbose_name = 'Lastname')
w_position = models.ForeignKey(to = Position, to_field = 'p_name', verbose_name = 'Position')
w_dept = models.ForeignKey(to = Department, to_field = 'd_name' verbose_name = 'Department')
形成
class WorkerForm(ModelForm):
class Meta:
model = Worker
widgets = {
'w_name' : TextInput(attrs = {'class': 'e name'}),
'w_lastame' : TextInput(attrs = {'class': 'e lastname'}),
'w_position': Select(attrs = {'class': 'e position'}),
'w_dept' : Select(attrs = {'class': 'e department'}),
}
admin.py中的定义
class WorkerAdmin(admin.ModelAdmin):
form = WorkerForm
list_display = ('w_name', 'w_lastname', 'w_position', 'w_dept')
怎么根据外键使选择框出现问题?
苏丹
您可以尝试在表单内重新声明表单的字段(确保使用与Model中相同的名称),然后在其中设置小部件和属性?
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