I've run this on my local windows machine and on an ubuntu server with the same results.
Query to run in PHP:
$job_sql="SELECT * FROM job WHERE job_title = 'SIP Opportunities where sipsubmitted EQ 1 and still in BAB PROCESS'";
$job_ret = mysql_query($job_sql);
$job_row = mysql_fetch_array($job_ret,MYSQL_ASSOC);
Error from PHP Script:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\\wamp\\www\\tracker\\inc\\common.php on line 489
Other similar queries work fine in same script (different job_titles).
phpMyAdmin:
SELECT *
FROM job
WHERE job_title = 'SIP Opportunities where sipsubmitted EQ 1 and still in BAB PROCESS'
LIMIT 0 , 30
Showing rows 0 - 0 (1 total, Query took 0.0004 sec) - successfully found the row!!!
Looks like you may have misplace a single quote in your example code. With the code as it is now, you're looking for the following job title:
'SIP Opportunities where sipsubmitted EQ 1 and still in BAB PROCESS'
Did you mean for that entire string to be the job_title
?
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