A more concise way is:
HttpServletRequest request = (HttpServletRequest) externalContext.getRequest();
String url = request.getRequestURL().toString();
String baseURL = url.substring(0, url.length() - request.getRequestURI().length()) + request.getContextPath() + "/";
Then you don't need to fiddle with omitting the ports when the scheme is http
and port is 80
and so on.
You can get ExternalContext
from FacesContext
and extract request
from External context then
String file = request.getRequestURI();
if (request.getQueryString() != null) {
file += '?' + request.getQueryString();
}
URL reconstructedURL = new URL(request.getScheme(),
request.getServerName(),
request.getServerPort(),
file);
reconstructedURL.toString();
This is the easiest way I've found that doesn't involve mysterious string manipulation on the various parts of the URL. It seems to work in all cases, including different protocols and ports.
String getAbsoluteApplicationUrl() throws URISyntaxException {
ExternalContext externalContext = FacesContext.getCurrentInstance().getExternalContext();
HttpServletRequest request = (HttpServletRequest) externalContext.getRequest();
URI uri = new URI(request.getRequestURL().toString());
newUri = new URI(uri.getScheme(), null,
uri.getHost(),
uri.getPort(),
request.getContextPath().toString(),null, null);
return newUri.toString();
}
I have one similar to BalusC's:
FacesContext context = FacesContext.getCurrentInstance();
HttpServletRequest request = (HttpServletRequest)context.getExternalContext().getRequest();
String requestURL = request.getRequestURL().toString();
String url = requestURL.substring(0, requestURL.lastIndexOf("/"));
Let me re-phrase Jigar's answer a bit:
final ExternalContext ectx = context.getExternalContext();
String url = ectx.getRequestScheme()
+ "://" + ectx.getRequestServerName()
+ ":" + ectx.getRequestServerPort()
+ "/" + ectx.getRequestContextPath();
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