I am trying to make a unique collection of dates in a Python list.
Only add a date to the collection if it not already present in the collection.
timestamps = []
timestamps = [
'2011-02-22', '2011-02-05', '2011-02-04', '2010-12-14', '2010-12-13',
'2010-12-12', '2010-12-11', '2010-12-07', '2010-12-02', '2010-11-30',
'2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16']
date = "2010-11-22"
if date not in timestamps:
timestamps.append(date)
How would I sort the list?
You can use sets for this.
date = "2010-11-22"
timestamps = set(['2011-02-22', '2011-02-05', '2011-02-04', '2010-12-14', '2010-12-13', '2010-12-12', '2010-12-11', '2010-12-07', '2010-12-02', '2010-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16'])
#then you can just update it like so
timestamps.update(['2010-11-16']) #if its in there it does nothing
timestamps.update(['2010-12-30']) # it does add it
This code will effectively do nothing. You are referencing the same variable twice ( timestamps
).
So you would have to make two seperate lists:
unique_timestamps= []
timestamps = ['2011-02-22', '2011-02-05', '2011-02-04', '2010-12-14', '2010-12-13', '2010-12-12', '2010-12-11', '2010-12-07', '2010-12-02', '2010-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16']
date="2010-11-22"
if(date not in timestamps):
unique_timestamps.append(date)
Your condition seems to be correct. If you do not care about the order of the dates though, it might be easier to use a set instead of a list. You would not need any if
in this case:
timestamps = set(['2011-02-22', '2011-02-05', '2011-02-04', '2010-12-14',
'2010-12-13', '2010-12-12', '2010-12-11', '2010-12-07',
'2010-12-02', '2010-11-30', '2010-11-26', '2010-11-23',
'2010-11-22', '2010-11-16'])
timesteps.add("2010-11-22")
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