I have an Oracle DB with a timestamp
field in it. What is the correct SQL code to insert a timestamp
into this field?
insert
into tablename (timestamp_value)
values (TO_TIMESTAMP(:ts_val, 'YYYY-MM-DD HH24:MI:SS'));
if you want the current time stamp to be inserted then:
insert
into tablename (timestamp_value)
values (CURRENT_TIMESTAMP);
INSERT
INTO mytable (timestamp_field)
VALUES (CURRENT_TIMESTAMP)
CURRENT_TIMESTAMP
and SYSTIMESTAMP
are Oracle reserved words for this purpose. They are the timestamp analog of SYSDATE
.
INSERT INTO TABLE_NAME (TIMESTAMP_VALUE) VALUES (TO_TIMESTAMP('2014-07-02 06:14:00.742000000', 'YYYY-MM-DD HH24:MI:SS.FF'));
Kind of depends on where the value you want to insert is coming from. If you want to insert the current time you can use CURRENT_TIMESTAMP
as shown in other answers (or SYSTIMESTAMP
).
If you have a time as a string and want to convert it to a timestamp, use an expression like
to_timestamp(:timestamp_as_string,'MM/DD/YYYY HH24:MI:SS.FF3')
The time format components are, I hope, self-explanatory, except that FF3
means 3 digits of sub-second precision. You can go as high as 6 digits of precision.
If you are inserting from an application, the best answer may depend on how the date/time value is stored in your language. For instance you can map certain Java objects directly to a TIMESTAMP
column, but you need to understand the JDBC
type mappings.
I prefer ANSI timestamp literals:
insert into the_table
(the_timestamp_column)
values
(timestamp '2017-10-12 21:22:23');
More details in the manual: https://docs.oracle.com/database/121/SQLRF/sql_elements003.htm#SQLRF51062
One can simply use
INSERT INTO MY_TABLE(MY_TIMESTAMP_FIELD)
VALUES (TIMESTAMP '2019-02-15 13:22:11.871+02:00');
This way you won't have to worry about date format string, just use default timestamp format.
Works with Oracle 11, have no idea if it does for earlier Oracle versions.
Inserting date in sql
insert
into tablename (timestamp_value)
values ('dd-mm-yyyy hh-mm-ss AM');
If suppose we wanted to insert system date
insert
into tablename (timestamp_value)
values (sysdate);
For my own future reference:
With cx_Oracle use cursor.setinputsize(...):
mycursor = connection.cursor();
mycursor.setinputsize( mytimestamp=cx_Oracle.TIMESTAMP );
params = { 'mytimestamp': timestampVar };
cusrsor.execute("INSERT INTO mytable (timestamp_field9 VALUES(:mytimestamp)", params);
No converting in the db needed. See Oracle Documentation
首先,您需要使该字段为 Nullable,然后如此简单 - 而不是放置一个值,而是放置这个代码CURRENT_TIMESTAMP
。
The below sample working fine for me.
INSERT INTO "DB"."TBL" (UPDATEDDATETIME)
VALUES (TO_TIMESTAMP('2022-07-12 17:16:05.551000000', 'YYYY-MM-DD HH24:MI:SS.FF'))
CREATE TABLE Table1 (
id int identity(1, 1) NOT NULL,
Somecolmn varchar (5),
LastChanged [timestamp] NOT NULL)
this works for mssql 2012
INSERT INTO Table1 VALUES('hello',DEFAULT)
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