I'm querying a bunch of cities from a zip-code table. I'd only like to grab results with an unique 'City'. (Lots of cities have multiple zips.) How could this be done?
$query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`,
( 3959 * acos( cos( radians('%s') ) * cos( radians( `Lat` ) ) *
cos( radians( `Long` ) - radians('%s') ) +
sin( radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance
FROM Zips HAVING distance < '%s' ORDER BY distance LIMIT 0 , 18",
mysql_real_escape_string($lat),
mysql_real_escape_string($lng),
mysql_real_escape_string($lat),
mysql_real_escape_string($radius));
$result = mysql_query($query, $dbConn);
You are using HAVING
at a wrong place WHERE
is needed here and use GROUP BY
to group result by city
$query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips WHERE distance < '%s'
GROUP BY City ORDER BY distance LIMIT 0 , 18",
EDIT
You could also try
$query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips HAVING distance < '%s'
GROUP BY City ORDER BY distance LIMIT 0 , 18";
OR
$query = sprintf("SELECT * FROM (SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips HAVING distance < '%s'
ORDER BY distance LIMIT 0 , 18 ) as result_set GROUP BY City";
try with
SELECT DISTINCT(city)
OR
GROUP BY (City)
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.