How to get focused node in dijit.Tree?
Question
是否有一种简单的方法来检索dijit.Tree中哪个树节点当前具有焦点/突出显示？
1 answers
solution1
1 ACCPTED 2011-04-26 02:03:22
There is no documentation for it, but the lastFocused property of the dijit.Tree instance can be used to obtain the node with the current focus. If no item has the current focus, the value will be null . The _onNodeFocus method of dijit/Tree.js indicates how the lastFocused property is used.
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