PHP script - detect whether running under linux or Windows?

Question

I have a PHP script that may be placed on a windows system or a linux system. I need to run different commands in either case.

How can I detect which environment I am in? (preferably something PHP rather than clever system hacks)

Update

To clarify, the script is running from the command line.

Answer 1

Check the value of the PHP_OS constant ^Docs .

It will give you various values on Windows like WIN32 , WINNT or Windows .

See as well: Possible Values For: PHP_OS and php_uname ^Docs :

if (strtoupper(substr(PHP_OS, 0, 3)) === 'WIN') {
    echo 'This is a server using Windows!';
} else {
    echo 'This is a server not using Windows!';
}

Answer 2

You can check if the directory separator is / (for unix/linux/mac) or \ on windows. The constant name is DIRECTORY_SEPARATOR .

if (DIRECTORY_SEPARATOR === '/') {
    // unix, linux, mac
}

if (DIRECTORY_SEPARATOR === '\\') {
    // windows
}

Answer 3

if (strncasecmp(PHP_OS, 'WIN', 3) == 0) {
    echo 'This is a server using Windows!';
} else {
    echo 'This is a server not using Windows!';
}

seems like a bit more elegant than the accepted answer. The aforementioned detection with DIRECTORY_SEPARATOR is the fastest, though.

Answer 4

Note that PHP_OS reports the OS that PHP was built on , which is not necessarily the same OS that it is currently running on.

If you are on PHP >= 5.3 and just need to know whether you're running on Windows or not-Windows then testing whether one of the Windows-specific constants is defined may be a good bet, eg:

$windows = defined('PHP_WINDOWS_VERSION_MAJOR');

Answer 5

Starting with PHP 7.2.0 you can detect the running OS using the constant PHP_OS_FAMILY :

if (PHP_OS_FAMILY === "Windows") {
  echo "Running on Windows";
} elseif (PHP_OS_FAMILY === "Linux") {
  echo "Running on Linux";
}

See the official PHP documentation for its possible values.

Answer 6

According to Predefined Constants: User Contributed Notes Volker's and rdcapasso solution, you can simply create helper class like this:

<?php

class System {

    const OS_UNKNOWN = 1;
    const OS_WIN = 2;
    const OS_LINUX = 3;
    const OS_OSX = 4;

    /**
     * @return int
     */
    static public function getOS() {
        switch (true) {
            case stristr(PHP_OS, 'DAR'): return self::OS_OSX;
            case stristr(PHP_OS, 'WIN'): return self::OS_WIN;
            case stristr(PHP_OS, 'LINUX'): return self::OS_LINUX;
            default : return self::OS_UNKNOWN;
        }
    }

}

Usage:

if(System::getOS() == System::OS_WIN) {
  // do something only on Windows platform
}

Answer 7

The php_uname function can be used to detect this.

echo php_uname();

Answer 8

This should work in PHP 4.3+:

if (strtolower(PHP_SHLIB_SUFFIX) === 'dll')
{
    // Windows
}
else
{
    // Linux/UNIX/OS X
}

Answer 9

To detect whether it's Windows, OS X or Linux:

if (stripos(PHP_OS, 'win') === 0) {
    // code for windows
} elseif (stripos(PHP_OS, 'darwin') === 0) {
    // code for OS X
} elseif (stripos(PHP_OS, 'linux') === 0) {
    // code for Linux
}

stripos is a bit slower than substr in this particular case, yet it's efficient enough for such a small task, and more elegant.

Answer 10

Core Predefined Constants: http://us3.php.net/manual/en/reserved.constants.php which has the PHP_OS (string) constant.

Or if you want to detect the OS of the client:

<?php
    echo $_SERVER['HTTP_USER_AGENT'] . "\n\n";

    $browser = get_browser(null, true);
    print_r($browser);
?>

From http://us3.php.net/manual/en/function.get-browser.php

---

According to your edit you can refer to this dublicate PHP Server Name from Command Line

You can use

string php_uname ([ string $mode = "a" ] )

So

php_uname("s")

's': Operating system name. eg. FreeBSD.

Would do the trick for you, see here http://php.net/manual/en/function.php-uname.php

Answer 11

You can check if a constant exists in PHP >5.3.0 ( manual )

if (defined('PHP_WINDOWS_VERSION_BUILD')) {
    // is Windows
}

Previously, this method was used in Symfony. Now they use a different method :

if ('\\' === DIRECTORY_SEPARATOR) {
    // is Windows
}

Answer 12

If you want to check if running under Linux, just test if (PHP_OS === 'Linux') . No need to use strtolower() and substr().

Answer 13

function isWin(){
 if (strtolower(substr(PHP_OS, 0, 3)) === 'win' || PHP_SHLIB_SUFFIX == 'dll' || PATH_SEPARATOR == ';') {
    return true;
 } else {
    return false;
 }
}

Answer 14

From http://www.php.net/manual/en/reserved.variables.server.php#102162 :

<?php
echo '<table border="1">';

foreach ($_SERVER as $k => $v){
    echo "<tr><td>" . $k ."</td><td>" . $v . "</td></tr>";
}

echo "</table>"
?>

This is the entire $_SERVER array... as ArtWorkAD has noted, by using the HTTP_USER_AGENT key, you can extract the OS more explicitly.