JavaScript - Math.random() - parameter

Question

What changes adding the parameter in Math.random() ?

For example:

Math.random() == Math.random(1234)

Answer 1

Math.random doesn't take params.

If you want to generate a random number between 2 intervals (a and b) you can use the formula:

math.random()*(b-a)+a

Answer 2

Read the specification :

15.8.2.14 random ( )

Returns a number value with positive sign, greater than or equal to 0 but less than 1, chosen randomly or pseudo randomly with approximately uniform distribution over that range, using an implementation-dependent algorithm or strategy. This function takes no arguments.

Answer 3

Nothing. There is no seed for Math.random in Javascript. Anything inside the function call will just be dropped.

Answer 4

No official parameters. Have a look here: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Math/random

The confusion is understandable. Several sites have a seed in the function since it came from C / Java. More information about this ignored parameter here: Math.random() - Not random

If you want a better random number get one from here http://www.random.org/clients/http/ - you will need to wrap it in some server based client - see here for more information Cross domain ajax request from javascript file without help of server side code

UPDATE: Emailed the creator of random.org - he replied he is working on a jsonp implementation...

Answer 5

它将忽略传递的参数。

Answer 6

它没有Math.random()没有任何参数... :)