I have a two generators. First generator sometimes needs to call second generator and yield back values it got from there:
def a():
for _b in b():
yield _b
def b():
yield 1
yield 2
for _a in a():
print _a
Is there a more elegant way to do this:
for _b in b():
yield _b
I've tried this:
yield *b()
But surely it doesn't work. I have Python 2.6.
I think you mean PEP380 . It's available from Python 3.3 . It looks like:
yield from b()
There is no special syntax for that in Python2. You just use a for-loop.
The a
function in your question is actually completely useless. You can just use b
in it's place.
You can use a generator expression. It's about as concise as the loop, plus it indicates that your code is primarily for producing a return value instead of a side effect.
def a():
return (_b for _b in b())
As phihag said, you can probably simply write a = b
if your code is really like this example, since a and b return the same sequence.
Well, in this simple example, you could just write a = b
or a = lambda: b
. But if a
adds elements of its own, you can use itertools.chain :
import itertools
def a():
return itertools.chain(['a-value'], b())
Bear in mind that although this variant may be shorter, for: yield
is a quite intuitive (and therefore easy to understand) pattern.
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