I am trying to show a dialog from one of my WPF view model commands however when i call ShowDialog()
it throws a System.ArgumentException
, I was wondering if anyone could give me a hint as to why?
Here is my code:
Public ReadOnly Property OpenParser As ICommand
Get
Return New RelayCommand(Sub(param As Object) OpenParserExecute(DirectCast(param, Frame)))
End Get
End Property
Public Sub OpenParserExecute(ByVal mFrame As Frame)
SaveParserExecute()
Dim mOpenDialog As OpenFileDialog = OpenDialog
If mOpenDialog.ShowDialog() Then ' Lines the throws the exception
CurrentParser = New ParserEditorModel(mOpenDialog.FileName)
mFrame.Navigate(New ParserEditor(CurrentParser))
End If
End Sub
StackTrace as requested:
at MS.Internal.Interop.HRESULT.ThrowIfFailed(String message)
at MS.Internal.AppModel.ShellUtil.GetShellItemForPath(String path)
at Microsoft.Win32.FileDialog.PrepareVistaDialog(IFileDialog dialog)
at Microsoft.Win32.FileDialog.RunVistaDialog(IntPtr hwndOwner)
at Microsoft.Win32.FileDialog.RunDialog(IntPtr hwndOwner)
at Microsoft.Win32.CommonDialog.ShowDialog()
at WinTransform.GUI.MainWindowModel.OpenParserExecute(Frame mFrame) in C:\Users\Alex\Desktop\MEDLI\branches\WinTransform\GUI\ViewModels\MainWindowModel.vb:line 38
Because ShowDialog()
itself returns a Nullable(Of Boolean)
and your If
statement is expecting a non-Nullable Boolean
.
You'll have to cast the dialog's return value to a Boolean
and if it's True
retreive the selected file through your dialog's Filename
property.
Example .
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