Syntax error trying to set up invalid character array

Question

I'm fairly new to PHP, and I'm setting up a "members area" for my site following this tutorial . There seems to be a problem with the code near the bottom of the page.

When trying to pick out the invalid characters from a username field, the array $junk is set up.

$junk = array('.' , ',' , '/' , '\' , '`' , ';' , '[' ,  ']' , '-', '_', '*', '&', '^',
'%', '$', '#', '@', '!', '~', '+', '(', ')', '|', '{', '}', '<', '>', '?', ':', '"', '='); 

This block of code returns a syntax error for me.

Now, my first thought was that either the '#' or the '(' and ')' was causing the problem, since they are commonly used in html and php. The error was still returned with them removed.

I am new to php, so it very well could be just some small syntax error I am missing. Any input would be great. Thanks!

EDIT: Also, if there is an easier way of doing this, please let me know!

Answer 1

对于'\\'字符，你需要写它

'\\'

Answer 2

The backslash needs to be escaped: '\\\\' . That's because \\' gives you a literal apostrophe, which you couldn't otherwise get inside a singly quoted string.

Answer 3

There is a much easier way to do this, regular expressions. If you want to set up the username to only accept alpha-numeric characters it's,

$user = preg_replace("/[^0-9a-zA-Z]+/", "", $user);

The expression essentially says, replace anything that is not 0-9, az, AZ with "". If you want to allow the "@", "." (period) and "-" and "_" symbols:

$user = preg_replace("/[^0-9a-zA-Z\@\.\-\_]+/", "", $user);

Regular expressions are a very powerful tool. They can be used in most languages, including javascript and PHP. So it is worth taking the time to learn them.

Answer 4

for a smaller array, make a string and then call str_split to get it as an array of chars.

$junk = str_split('.,/\\`;[]-_*&^%S#@!~+()|{}<>?:"=')

Personally I would have used the chars in the following order

~`!@#$%^&*()-_+={}[]\|;:'",.<>/?

Since that is how they are on my keyboard. But that's just a minor issue. I knows the ' (single quote) is missing from the original string.

Better ways to validate input involve regular expressions.