Check if more than one value is in an array

Question

I want to check if the numbers 7, 86 and 99 exist in a array called $category .

So far I have this, but I don't want to use three lines to do it:

if (in_array("7", $category)) {  //do something  }

Answer 1

$search = array("7", "86", "99");

If the ids are the keys of the $category variable:

if (count(array_intersect($search, array_keys($category))) == count($search)) {
  // all found
}
if (count(array_intersect($search, array_keys($category))) > 0) {
  // some found
}

If the ids are the values of the $category variable:

if (count(array_intersect($search, $category)) == count($search)) {
  // all found
}
if (count(array_intersect($search, $category)) > 0) {
  // some found
}

Answer 2

array_diff比较数组m，n并返回m中不包含n的任何元素。

count( array_diff( array(7,86,99), $category ) )

Answer 3

if (in_array("7", $category) + in_array("86", $category) + in_array("99", $category) >= 2)
   echo "at least two is exist in the array";

Update: use >= 1 or ||