SQL COUNT() WHERE multiple values

Question

I'll make this post short: I want to count the number of times my row appears in my table where the row is a specific value And another row could be 4 different values. I'll post my "guess" which doesn't work:

SELECT hero_selected, COUNT(hero_type) FROM heroes WHERE hero_type = 'agi' AND hero_selected = 'yt' OR hero_selected = 'yb' OR hero_selected = 'ym' OR hero_selected = 'yf

INFORMATION ABOUT THE TABLE

TABLE NAME
heroes

ROW TO COUNT
hero_type

SELECT "hero_type" WHERE
Value is 'agi'

ONLY SELECT IT WHERE "hero_selected" IS
Either yt , yb , ym or yf

If possible I'd also appreciate the full code including an echo of the count amount in php. Thanks A LOT in advance: :)

Answer 1

SELECT COUNT(*) 
FROM heroes 
WHERE hero_type = 'agi' AND hero_selected IN ('yt', 'yb', 'ym', 'yf')

Answer 2

From what I can glean from your question, you want this query

SELECT COUNT(1) FROM heroes
WHERE hero_type = 'agi'
AND hero_selected IN ('yt', 'yb', 'ym', 'yf')

PHP code might look like this

$db = new PDO(...);
$stmt = $db->query($query);
$count = $stmt->fetchColumn();
echo $count;

I'm assuming here that you only want a single count, not one per different hero_selected value as the other answers are indicating