I wanted to get image url "http://www.test.com/image.jpg" out from the string:
"<img align="right" alt="Title " src="http://www.test.com/image.jpg" width="120" /><"
Here is the code that i have:
module MyHelper
def getMymage(allDesc)
allDesc = "<img align="right" alt="Title " src="http://www.test.com/image.jpg" width="120" /><"
allDesc = allDesc.scan(src="(\S+)")
end
end
I got the following error: syntax error, unexpected tAMPER allDesc = allDesc.scan(src="(\\S+)")
syntax error, unexpected $undefined allDesc = allDesc.scan(src="(\\S+)")
How to fix it?
Thanks in advanced.
无法评论sunkencity的答案,但是解决破折号问题的正则表达式是:
/src=\"([a-z0-9_.\-:\/]+)"/i
The regexp is missing a start "/" and some extra stuff
allDesc.scan(/src=\"([a-z0-9_.\-:\/]+)"/i)
but you get an array as a response:
=> [["http://www.test.com/image.jpg"]]
I'd suggest using the matching operator and then use the first match variable:
allDesc =~ /(http:\/\/[a-z0-9_.-i\/]+)/ && $1
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