ASSEMBLY Offset to C++ Code question

Question

I've been trying to convert this code to C++ without any inlining and I cannot figure it out..

Say you got this line

sub     edx, (offset loc_42C1F5+5)

My hex-rays gives me

edx -= (uint)((char*)loc_42C1F5 + 5))

But how would it really look like without the loc_42C1F5 .

I would think it would be

edx -= 0x42C1FA;

But is that correct? (can't really step this code in any assembler-level debugger.. as it's damaged well protected)

loc_42C1F5 is a label actually..

seg000:0042C1F5 loc_42C1F5:                             ; DATA XREF: sub_4464A0+2B5o
seg000:0042C1F5                 mov     edx, [esi+4D98h]
seg000:0042C1FB                 lea     ebx, [esi+4D78h]
seg000:0042C201                 xor     eax, eax
seg000:0042C203                 xor     ecx, ecx
seg000:0042C205                 mov     [ebx], eax

Answer 1

loc_42C1F5 is a symbol. Given the information you've provided, I cannot say what its offset is. It may be 0x42C1F5 or it may be something else entirely.

If it is 0x42C1F5, then your translation should be correct.

Answer 2

IDA has incorrectly identified 0x42C1FA as an offset, and Hex-Rays used that interpretation. Just convert it to plain number (press O) and all will be well. That's why it's called Interactive Disassembler :)