简体   繁体   中英

How to generate a `kwargs` list?

From an external file I generate the following dictionary:

mydict = { 'foo' : 123, 'bar' : 456 }

Given a function that takes a **kwargs argument, how can generate the keyword-args from that dictionary?

def foo(**kwargs):
    pass

foo(**{ 'foo' : 123, 'bar' : 456 })

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM