Convert loop and if statemnt to a list comprehension

Question

Is it possible to convert the following to a python list comprehension:

values = [a,b,c,d,...]

converted_values = []
for item in values:
    if type(item) == datetime.date:
        converted_values.append(item)
    else:
        converted_values.append(item.decode('utf-8'))

Answer 1

You can use Conditional Expressions to make this work.

converted_values = [item if type(item) == datetime.data
                    else item.decode('utf-8')
                    for item in values]

Python conditionals are fairly readable. Here's some examples to show how they work:

print("yes" if True else "no") # prints "yes"
print("yes" if False else "no") # prints "no"

Answer 2

converted_values = [item if type(item) == datetime.date else item.decode('utf-8')
                       for item in values]

I assume you meant utf-8 .

Also, the Python docs recommend using isinstance(item, datetime.date) rather than type(item) == datetime.date .