So I have a data type
data SomeType a =
Type a |
Mix (SomeType a) (SomeType a)
This my show instance for SomeType
instance (Show a) => Show (SomeType a) where
show (Type a) = show a
show (Mix a b) = "(" ++ show a ++ " " ++ show b ++ ")"
So
Mix (Type 5) (Type 4)
would give me
(5 4)
Now I want to have
read "(3 4)" :: SomeType Int
produce
(3 4)
or
read "(a b)" :: SomeType Char
produce
(a b)
I am lost at how to use the Read class.
Here's an example based on the documentation which should be able to parse everything that show
renders (assuming the type has a compatible Read
instance defined), that is read . show
read . show
should be more or less the identity:
instance (Read a) => Read (SomeType a) where
readsPrec d r = readMix r ++ readType r
where
readMix = readParen True $ \r -> do
(v1, r'') <- readsPrec d r
(v2, r') <- readsPrec d r''
return (Mix v1 v2, r')
readType r = do
(v, r') <- readsPrec d r
return (Type v, r')
Thus,
> read "(3 4)" :: SomeType Int
(3 4)
it :: SomeType Int
But note, that for SomeType Char
the default Show
instance of Char
surrounds the character with single quotes:
> read "('a' ('b' 'c'))" :: SomeType Char
('a' ('b' 'c'))
it :: SomeType Char
hope this helps
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