How do I get the .exe name of a C# console application?

Question

I'm debugging "xiixtasks.exe", a C# console-mode application in VS2008.

I'm trying to get the version info from xiixtasks.exe.

When I try "Process.GetCurrentProcess()", it gives me the filename and version info for vshost.exe, NOT xiixtasks.exe:

  // WRONG: this gives me xiixtasks.vhost.exe, version 9.0.30729.1
  //        I *want* "xiixtasks.exe", version 1.0.0.1024
  System.Diagnostics.FileVersionInfo fi =
    System.Diagnostics.Process.GetCurrentProcess().MainModule.FileVersionInfo;

What should I be doing instead?

Thank you in advance!

======================================================

Solution:

1) The initial problem was indeed the IDE's "vshost" wrapper. One workaround would have been to change the build settings.

2) Assembly.GetExecutingAssembly().CodeBase is an excellent solution - thank you!. It works inside and outside the debugger.

3) Unfortunately, when I tried calling it with a function that expected a normal file path (instead of a URI like GetExecutingAssembly()" gives you), it died with a "Uri formats are not supported" exception.

4) Final solution: call GetExecutingAssembly(), then Uri.LocalPath ():

...
else if (cmdArgs.cmd.Equals(CmdOptions.CMD_SHOW_VERSION))
{
    string codeBaseUri = 
       Urifile.System.Reflection.Assembly.GetExecutingAssembly().CodeBase;
    string codeBase =
        new Uri (codeBaseUri).LocalPath;
    string sVersion = Util.GetWindowsVersion(codeBase);
    System.Console.WriteLine ("version({0}): {1}: ",
        Util.Basename(codeBase), sVersion);
}

Thank you once again, all!

Answer 1

Full Path of your assembly:

Assembly.GetExecutingAssembly().CodeBase.Dump();

You can always extract the name with Path.GetFileName :

string codeBase = Assembly.GetExecutingAssembly().CodeBase;
string name = Path.GetFileName(codeBase);

Answer 2

It sounds like you are running inside the IDE in debug with the "Enable the Visual Studio hosting process" checkbox enabled. In which case, the current process is xiixtasks.vshost.exe - it is a shell exe used to help debugging. You need to disable that checkbox.

Answer 3

Depending on what info you want, you can use a variety of calls:

Answer 4

Try this to get the version:

System.Reflection.Assembly.GetExecutingAssembly().GetName().Version

And this to get the name:

System.Reflection.Assembly.GetExecutingAssembly().GetName().ToString()

Answer 5

This would also get you name / version

name: Assembly.GetExecutingAssembly().GetName().Name
version: = Assembly.GetExecutingAssembly().GetName().Version

Answer 6

That's actually what I would expect as it is in fact executing the vshost file in debug mode.

If you don't want it to execute the vshost file but rather your exe directly, you need to go into your project settings and disable the vshost debugging option.

Answer 7

'vshost.exe'包装器通常只对Debug版本启用，也没有必要使用它，所以也许您应该考虑在项目设置下关闭它（Debug选项卡，取消选中'启用Visual Studio托管进程'在底部）。

Answer 8

If you will get the exception like "URI format is not supported" While Copying the xml file from one directory to the another by using the following code.

string path=System.IO.Path.GetDirectoryName(Assembly.GetExecutingAssembly().CodeBase);
DirectoryInfo dir=new DirectoryInfo(path+"\\App2");
FileInfo[] Files=dir.GetFiles();

then convert it into the URI like.

string path =Path.GetDirectoryName(Assembly.GetExecutingAssembly().CodeBase); 
URI uri = new URI(path); 
string FileName = Path.Combine(uri.LocalPath, "\\App2"+file.Name);

then use it to get the files.

Answer 9

尝试

var asm = Assembly.GetExecutingAssembly();