SQL Query Error in Oracle

Question

On Exeuting Following Query:

SELECT ID
  FROM INSTITUTE
 WHERE MEMBER_ID IN (
    SELECT ID 
      FROM MEMBER 
     WHERE ID IN (765,769,753,774,778,779,781,790,799,809,
                  820,823,855,835,839,842,845,849,850,851)
    ORDER BY NAME ASC
)

I am getting following error:

ORA-00907: missing right parenthesis
00907. 00000 -  "missing right parenthesis"
*Cause:    
*Action:
Error at Line: 5 Column: 81

How can I troubleshoot this bug???

Answer 1

Your ORDER BY is inside your subselect and therefore useless to the final order of the results but is causing your error.

Move it outside the subselect.

SELECT id
  FROM institute
 WHERE member_id IN
          (  SELECT id
               FROM MEMBER
              WHERE id IN ( 765, 769, 753, 774, 778, 779, 781, 790,
                            799, 809, 820, 823, 855, 835, 839, 842,
                            845, 849, 850, 851 )
          )
 ORDER BY name ASC

NB: I can only assume that name is a column in the institute table as otherwise the ORDER BY would be totally redundant. Therefore it should be ordering the main SELECT .

or remove it entirely...

SELECT id
  FROM institute
 WHERE member_id IN
          (  SELECT id
               FROM MEMBER
              WHERE id IN ( 765, 769, 753, 774, 778, 779, 781, 790,
                            799, 809, 820, 823, 855, 835, 839, 842,
                            845, 849, 850, 851 )
          )

Wouldn't this query be more efficient though?

SELECT i.id
  FROM institute i
 INNER JOIN member m
    ON (i.member_id = m.id)
 WHERE m.id IN ( 765, 769, 753, 774, 778, 779, 781, 790,
                 799, 809, 820, 823, 855, 835, 839, 842,
                 845, 849, 850, 851 )

Answer 2

Your ORDER BY in the sub-select is useless. Consider joining the two tables instead, like this:

SELECT ID
FROM INSTITUTE i, MEMBER m
WHERE
i.MEMBER_ID = m.ID
AND i.MEMBER_ID IN
    (
        765,769,753,774,778,779,781,790,799,809,820,823,855,835,839,842,845,849,850,851
    )
ORDER BY m.NAME

Answer 3

order by should bu put out of the IN clause

SELECT ID
FROM INSTITUTE
WHERE MEMBER_ID IN (
SELECT ID FROM MEMBER WHERE ID IN (
765,769,753,774,778,779,781,790,799,809,820,823,855,835,839,842,845,849,850,851 )
)
ORDER BY NAME ASC

Answer 4

Try this -

SELECT ID 
FROM INSTITUTE 
WHERE MEMBER_ID IN (
SELECT ID FROM MEMBER WHERE ID IN (765,769,753,774,778,779,781,790,799,809,820,823,855,835,839,842,845,849,850,851))
ORDER BY NAME ASC

I suspect you need the ORDER BY statement outside of the IN clause

Answer 5

SELECT ID FROM INSTITUTE 
WHERE MEMBER_ID IN ( SELECT ID FROM MEMBER WHERE ID IN
( 765,769,753,774,778,779,781,790,799,809,820,823,855,835,839,842,845,849,850,851 )) ORDER BY NAME ASC;

Try this - your order by is in the wrong place.

Answer 6

This is likely because your ORDER BY clause occurs inside the outer MEMBER_ID IN(...) clause.

This query looks suspiciously as though it should be accomplished with a JOIN instead of two IN() clauses:

SELECT INSTITUTE.id
FROM 
  INSTITUTE JOIN MEMBER ON INSTITUTE.MEMBER_ID = MEMBER.ID
WHERE MEMBER.ID IN IN (765,769,753,774,778,779,781,790,799,809,820,823,855,835,839,842,845,849,850,851)
ORDER BY MEMBER.NAME ASC

Answer 7

The order by in the subquery is completely useless, it won't order the output at all. Remove it and it will work.

Btw, moving it outside won't give the expected result, except institute.name has the same values as member.name ;-)