xsl with xml with attribute in root element does not work
Question
I use a sw that generates a xml file and i'd like to present that file in an html file, so i begun to create a xsl file to do that for me. The problem is that i don't know how to address the errorlist root element due to the attributes. If i delete the attributes from the xml file the xsl works fine.
My xml file is:
<errorList xmlns="http://www.klocwork.com/inForce/report/1.0" version="9.1.0">
<problem>
<problemID>1</problemID>
<file>stdafx.h</file>
</problem>
<problem>
...
</problem>
</errorList>
My xsl so far is:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>Issues</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>ProblemID</th>
<th>File</th>
</tr>
<tr>
<td><xsl:value-of select="errorList/problem/problemID"/></td>
<td><xsl:value-of select="errorList/problem/file"/></td>
</tr>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
The problem is that if the attributes are present in the 'errorList' tag the output is a table with no lines but if i remove the attributes it works fine.
2 answers
solution1
4 2011-11-17 11:30:26
Add namespace declaration to XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:k="http://www.klocwork.com/inForce/report/1.0">
Then use it:
<xsl:value-of select="k:errorList/k:problem/k:problemID"/>
solution2
3 2011-11-17 11:21:41
<xsl:stylesheet version="1.0"
xmlns:k="http://www.klocwork.com/inForce/report/1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
and then reference it as k:errorList .
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