I have this query that uses a UNION:
$this->db->query('
SELECT DISTINCT users.user_pic, users.id, users.username, contacts.accepted
FROM users
LEFT JOIN contacts ON users.id = contacts.user_1
WHERE contacts.user_2 = ' . $this->session->userdata('user_id') . '
UNION DISTINCT
SELECT DISTINCT users.user_pic, users.id, users.username, contacts.accepted
FROM users
LEFT JOIN contacts ON users.id = contacts.user_2
WHERE user_1 = ' . $this->session->userdata('user_id')
);
Is there a way to see if the sessions 'user_id' was encountered in contacts.user_1 or contacts.user_2 ? Maybe by changing the query, or if i can use some if statements in the view?
Thanks in advance
George
yes you can add another field to select , that you can recognise like (1,2)
$this->db->query('
SELECT 1 as table_id,DISTINCT users.user_pic, users.id, users.username, contacts.accepted
FROM users
LEFT JOIN contacts ON users.id = contacts.user_1
WHERE contacts.user_2 = ' . $this->session->userdata('user_id') . '
UNION DISTINCT
SELECT 2 as table_id,DISTINCT users.user_pic, users.id, users.username, contacts.accepted
FROM users
LEFT JOIN contacts ON users.id = contacts.user_2
WHERE user_1 = ' . $this->session->userdata('user_id')
);
I typically use:
$id = $this->session->userdata('user_id');
then use $id in the query. Reads cleaner and on MySQL at least, if the query fails, it lists the value of $id. Never tried calling the session in the query before.
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