I have some html like this
<form id="reportform" method='post'>
<input type='hidden' id='qid' name='qid' value="<?php echo $id ?>" />
<span><input type="radio" id="reporttp" name="reporttp" value="spam" /> spam</span>
<span><input type="radio" id="reporttp" name="reporttp" value="attack" /> attacking</span>
<span><input type="radio" id="reporttp" name="reporttp" value="nonsense" /> nonsense</span>
<span><input type="radio" id="reporttp" name="reporttp" value="other" /> other</span
<input type="image" name='Submit' value='Submit' src="../Images/buttons/reportButton.png"/>
</form>
when i try to read the value in $('#reportform').submit(function() {
i read it as $(reportttp).attr("value")
. And then i did some posting (which works fine). The problem is I always get "spam" postedf to me even though i select the other radio boxes. If i switch the first and second radio button around, ill get "attacking".... Could you tell me what is wrong?
You cannot have multiple elements with the same id
I assume you want to read the checked radio button's value? Is so, give them all unique ids, then do:
$("input[type='radio']:checked", "#reportform").val();
This will grab all radio buttons inside of you reportform
, grab the checked one, then retrieve its value.
我的猜测是,每个单选按钮的名称和ID都相同,从而导致浏览器任意做出奇怪的决定。
In addition to Adam's answer, this is also invalid:
$(reportttp).attr("value")
should be
$('input[name="reportttp"]').val()
and I hereby retract my statement cause Adam updated his answer to a much better one.
and get rid of the duplicate id's
您应该能够执行$('#reportttp')。val()以获取选定的值。
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