Display SQL Table in PHP
Question
I am trying to display a table in php. I have established a valid connection. I get the error:
Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in /Applications/XAMPP/xamppfiles/htdocs/project.php on line 17
The page's code:
<html>
<head>
<title>PHP Site Michael Mazur</title>
</head>
<body>
<?php
//connect to DB
$con=mysql_connect("localhost","mike","mike");
$db_found = mysql_select_db("my_guitar_shop2");
$result = mysql_query("SELECT firstName,lastName FROM customers");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['firstName'] . "</td>";
echo "<td>" . $row['lastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
</body>
</html>
2 answers
solution1
5 ACCPTED 2011-12-08 21:19:12
The rest of your while loop could look like this
while($row = mysql_fetch_array($result)){
print "<tr><td>".$row['Firstname']."</td><td>".$row['Lastname']."</td></tr>";
}
print "</table>";
Try putting these lines on a single line as i have done above.
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
like
echo "<table border='1'><tr><th>Firstname</th><th>Lastname</th></tr>";
Other useful options here.
solution2
0 2011-12-08 21:12:47
Given that part of the page's code is missing, this is only a guess. But it looks like part of your problem is that you've double-selected the database (a no-no).
Also, the while statement looks slightly suspect (no opening brace to verify context).
Additionally, if you are going to pass $con to the database selector, you should also pass it to the mysql_query calls (good practice for readability).
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