in_array unexpected results

Question

Hello I have an array that looks likes this,

    Array
(
    [0] => 40's
    [1] =>  50's
    [2] =>  60's
)

and some code that looks like this,

<?php if(isset($playable_age) && in_array('40\'s', $playable_age)) { $set = TRUE; } else { $set = FALSE; } ?>
<div class="checkbox"><?php echo $this->formbuilder->checkbox( 'playable_age[]', "40's", "40's", $set ); ?></div>
<?php if(isset($playable_age) && in_array('50\'s', $playable_age)) { $set = TRUE; } else { $set = FALSE; } ?>
<div class="checkbox"><?php echo $this->formbuilder->checkbox( 'playable_age[]', "50's", "50's", $set ); ?></div>
<?php if(isset($playable_age) && in_array('60\'s', $playable_age)) { $set = TRUE; } else { $set = FALSE; } ?>
<div class="checkbox"><?php echo $this->formbuilder->checkbox( 'playable_age[]', "60's", "60's", $set ); ?></div>

Now the first if statement returns true, however the 2nd and 3rd if return false even though the 50's and 60's values exist in the array why is this?

Answer 1

Looks like there is a space before these values in the array:

[1] =>  50's
[2] =>  60's
       ^

Something not seen with the first value:

[0] => 40's

Answer 2

Because you have a syntax error.

You can do this:

<?php 
$playable_age = array(0=>'40\'s',1=>'50\'s',2=>'60\'s');
if(isset($playable_age) && in_array('40\'s', $playable_age)) { $set = TRUE; echo "1"; } else { $set = FALSE; echo "2"; } 
if(isset($playable_age) && in_array('50\'s', $playable_age)) { $set = TRUE; echo "3"; } else { $set = FALSE; echo "4"; } 
if(isset($playable_age) && in_array('60\'s', $playable_age)) { $set = TRUE; echo "5"; } else { $set = FALSE; echo "6"; } 
if(isset($playable_age) && in_array('70\'s', $playable_age)) { $set = TRUE; echo "7"; } else { $set = FALSE; echo "8"; } 
?>

Answer 3

在对数组执行逻辑检查之前，创建一个用户定义的函数并使用array_walk调用它以对每个数组值进行trim（）。