How to put JSP in WEB-INF correct?

Question

I'm using MVC and want to put my JSP pages in WEB-INF to avoid direct access to it. I have an index.jsp page and other pages in jsp folder in Web Content and it works. It looks like this:

-Web Content
-index.jsp
-jsp
--main_read.jsp
--...

By the way, index.jsp is my login page and whether user is logged, in controller I use

RequestDispatcher dispatcher =
        getServletContext().getRequestDispatcher("jsp/main_read.jsp");
dispatcher.forward(request, response);

I works perfect, but when I'm trying to put my JSP in WEB-INF it fails:

-Web Content
-index.jsp
-WEB-INF
--jsp
---jsp
----main_read.jsp
----...

And gives an error like this

HTTP Status 404 - /Libruary/jsp/main_read.jsp

type Status report

message /Libruary/jsp/main_read.jsp

description The requested resource (/Libruary/jsp/main_read.jsp) is not available.
Apache Tomcat/6.0.26

Probably the problem is in the page path, I write in dispatcher.forward , but anyway, help me please.

Answer 1

You seem to pass the path /jsp/main_read.jsp , and the JSP is in /WEB-INF/jsp/jsp/main_read.jsp . Obviously, the paths don't match. Pass the correct path to getRequestDispatcher() : /WEB-INF/jsp/jsp/main_read.jsp .

The javadoc says:

The pathname must begin with a / and is interpreted as relative to the current context root