how to select sum of column based on date

Question

I have the following table in a database. I want to be able to get the sum of the value colum but only based on the date. so if today was january 1st i only want the sum for every value that has jan 1st as the date. I am using the following:

SELECT SUM(value) AS value_today FROM table_value GROUP BY date ORDER BY date DESC

Only problem is that it only returns the sum for december 22 and nothing new entered into the database.

+-------+---------+------------+
| ID    | value   | date       |
+-------+---------+------------+
|   1   |   3     | 2011-12-22 |
|   2   |   2     | 2011-12-22 |
|   3   |   4     | 2011-12-22 |
|   4   |   2     | 2012-01-01 |
+-------+---------+------------+

Answer 1

SELECT SUM(value) AS value_today FROM table_value WHERE date = CURDATE()

Something like this?

If it is not, maybe you can rephrase your question.

Answer 2

SELECT SUM(value) AS value_today FROM table_value WHERE date = DATE(NOW())

这样，您只能检索今天的数据总和。

Answer 3

SELECT sum(value), date FROM table WHERE date = 2012-01-01 ORDER BY date DESC