There are two tables with the same structure: 'imsc_storage_users' & 'imsc_storage_users_archive'.
My current SELECT/UNION:
SELECT `cli`,`ts`,`questions`, `answers`,`correct`,`last`,`minutes`
FROM `imsc_storage_users`
UNION DISTINCT
SELECT `cli`,`ts`,`questions`, `answers`,`correct`,`last`,`minutes`
FROM `imsc_storage_users_archive`
ORDER BY `correct` DESC,`minutes` ASC
I'm getting these results:
+--------------+---------------------+-----------+---------+---------+------+---------+
| cli | ts | questions | answers | correct | last | minutes |
+--------------+---------------------+-----------+---------+---------+------+---------+
| 111111111111 | 2011-12-22 11:13:57 | 30 | 29 | 14 | 30 | 1305.47 |
| 222222222222 | 2011-12-15 13:39:16 | 26 | 24 | 13 | 24 | 15.67 |
| 333333333333 | 2011-12-15 13:39:39 | 26 | 25 | 11 | 25 | 15.18 |
| 444444444444 | 2011-12-15 13:39:39 | 25 | 21 | 11 | 25 | 280.53 |
| 111111111111 | 2011-12-22 11:13:57 | 25 | 21 | 10 | 25 | 373.87 |
| 555555555555 | 2011-12-19 15:46:15 | 11 | 10 | 5 | 10 | 3.8 |
| 666666666666 | 2011-12-15 13:39:16 | 14 | 10 | 4 | 10 | 321.64 |
| 777777777777 | 2011-12-19 08:34:36 | 15 | 11 | 4 | 13 | 474.66 |
Notice that '111111111111' appears twice?
I want it to be combined, so in the results set I get one row of '111111111111' which combines/sums all fields; 'questions' =>> 55.... etc' .
What would be the correct SQL?
Performance are NOT of an issue here.
Thank you!
SELECT `cli`,max(`ts`) AS ts, sum(`questions`) as questions, sum(`answers`) as answers,sum(`correct`) as correct,sum(`last`) as last,sum(`minutes`) as minutes
FROM (
SELECT `cli`,`ts`,`questions`, `answers`,`correct`,`last`,`minutes`
FROM `imsc_storage_users`
UNION ALL
SELECT `cli`,`ts`,`questions`, `answers`,`correct`,`last`,`minutes`
FROM `imsc_storage_users_archive`
) AS baseview
GROUP BY cli
ORDER BY `correct` DESC,`minutes` ASC
Try:
SELECT `cli`,
`ts`,
sum(`questions`),
sum(`answers`),
sum(`correct`),
sum(`last`),
sum(`minutes`)
FROM (SELECT `cli`,`ts`,`questions`, `answers`,`correct`,`last`,`minutes`
FROM `imsc_storage_users`
UNION ALL
SELECT `cli`,`ts`,`questions`, `answers`,`correct`,`last`,`minutes`
FROM `imsc_storage_users_archive`) V
group by `cli`, `ts`
ORDER BY 5 DESC, 7 ASC
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