In C/C++, comparison operators such as < >
have higher priority than ==
does, right?
So in C/C++, the code will evaluate to true
or 1
:
if(3<4 == 2<3) { //3<4 == 2<3 will evaluate to true, right?
...
}
But in Python, it seems wrong:
3<4 == 2<3 #this will evaluate to False in Python.
Question
In Python, does every comparison operator have the same priority?
In Python, not only do comparison operators gave the same priority, they are treated specially (they chain rather than group). From the documentation :
Formally, if
a, b, c, ..., y, z
are expressions andop1, op2, ..., opN
are comparison operators, thena op1 b op2 c ... y opN z
is equivalent toa op1 b and b op2 c and ... and y opN z
, except that each expression is evaluated at most once.
In your case, the expression
3<4 == 2<3
is equivalent to
3 < 4 and 4 == 2 and 2 < 3
which is False
due to the second clause.
Short answer: yeah, all the comparisons have the same precedence
Long answer: you may want to have a look on the documentation: Precedence on Python
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