#include<stdio.h>
#include<malloc.h>
typedef struct Node {
int data;
struct Node * next;
} Node;
void push(Node **headRef, int i){
//why does headRef == NULL in below if condition gives segmentation fault?
if(*headRef == NULL){
*headRef = malloc(sizeof(Node));
Node *head = *headRef;
head->data = i;
}
}
int main(int argc, char ** argv){
Node *head = NULL;
push(&head, 2);
printf("%d\n", head->data);
}
This code is of linked list where I try to push some data into the list. My question is in the comment of push function.
是的,segfault稍后会在head->data
访问中(如果您使用headRef==NULL
)
No need for the test. If *headRef happens to be NULL, newnode->next will be set to NULL, otherwise to *headRef.
void push(Node **headRef, int i){
Node *new;
new = malloc(sizeof *new);
/* check for new==NULL omitted */
new->next = *headRef;
new->data = i;
*headRef = new;
}
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