I need the id of the last inserted object. I use prepared statements to avoid sql injection. But i'm not sure how to obtain the id.
$sql = "INSERT IGNORE INTO faculty (id, term, role, prefix, first_name,
middle_name, last_name, suffix) VALUES (?,?,?,?,?,?,?,?)";
if (!($stmt = $mysqli->prepare($sql)))
echo "Faculty Prepare failed: (" . $mysqli->errno . ") " . $mysqli->error;
$stmt->bind_param('sissssss',
$faculty['id'],
$faculty['term'],
$faculty['role'],
$faculty->name->prefix,
$faculty->name->first,
$faculty->name->middle,
$faculty->name->last,
$faculty->name->suffix
);
if (!$stmt->execute())
echo "Faculty Execute failed: (" . $mysqli->errno . ") " . $mysqli->error;
$result = $stmt->insert_id;
echo "\n Result:" . $result;
$stmt->close();
The result is 0 always despite there being an entry in the database
Solution The element was being inserted into the database. The problem was when I had created the table id wasn't an integer it was a varchar which represented an employee id. To fix this, i added the employee id as an additional column in the table and used the default id int auto_increment primary key and it worked.
Try changing $result = $stmt->get_result();
to $result = $stmt->insert_id;
get_result()
is more for SELECT
queries, rather than INSERT
s.
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