I want to fetch data from website. I am using HtmlAgilityPack (C#). In the website content is like this
<div id="list">
<div class="list1">
<a href="example1.com" class="href1" >A1</a>
<a href="example4.com" class="href2" />
</div>
<div class="list2">
<a href="example2.com" class="href1" >A2</a>
<a href="example5.com" class="href2" />
</div>
<div class="list3">
<a href="example3.com" class="href1" >A3</a>
<a href="example6.com" class="href2" />
</div>
<div class="list3">
<a href="example4.com" class="href1" >A4</a>
<a href="example6.com" class="href2" />
</div>
<div class="list3">
<a href="example5.com" class="href1" >A5</a>
<a href="example6.com" class="href2" />
</div><div class="list3">
<a href="example6.com" class="href1" >A6</a>
<a href="example6.com" class="href2" />
</div><div class="list3">
<a href="example3.com" class="href1" >A7</a>
<a href="example6.com" class="href2" />
</div>
</div>
Here, we have 7 links with class="href1". I want to fetch only 3 links (from 3rd link to 5th link). How to fetch these particular links?
This kind of code:
HtmlDocument doc = new HtmlDocument();
doc.Load(myHtmlFile);
foreach (HtmlNode node in doc.DocumentNode.SelectNodes(
"//div[@class='list3' and position() > 2 and position() < 6]/a[@class='href1']"))
{
Console.WriteLine("node:" + node.InnerText);
}
will give you this result:
node:A3
node:A4
node:A5
Your data already appears to be well-formed XML. If you're parsing XHTML pages, then you could probably get away with the System.Xml
classes of the .NET Framework. For example, to load your data into an XElement
, you could use:
XElement xElement = XElement.Parse(@"
<div id=""list"">
<div class=""list1"">
<a href=""example1.com"" class=""href1"" >A1</a>
<a href=""example4.com"" class=""href2"" />
</div>
<div class=""list2"">
<a href=""example2.com"" class=""href1"" >A2</a>
<a href=""example5.com"" class=""href2"" />
</div>
<div class=""list3"">
<a href=""example3.com"" class=""href1"" >A3</a>
<a href=""example6.com"" class=""href2"" />
</div>
<div class=""list3"">
<a href=""example4.com"" class=""href1"" >A4</a>
<a href=""example6.com"" class=""href2"" />
</div>
<div class=""list3"">
<a href=""example5.com"" class=""href1"" >A5</a>
<a href=""example6.com"" class=""href2"" />
</div>
<div class=""list3"">
<a href=""example6.com"" class=""href1"" >A6</a>
<a href=""example6.com"" class=""href2"" />
</div>
<div class=""list3"">
<a href=""example3.com"" class=""href1"" >A7</a>
<a href=""example6.com"" class=""href2"" />
</div>
</div>");
Then, to select the third to fifth <a>
elements whose class
attribute has a value of href1
, use:
var links = xElement.XPathSelectElements("//a[@class='href1']").Skip(2).Take(3).ToList();
If, on the other hand, you have an HtmlAgilityPack.HtmlDocument
instance, you could execute an XPath query using:
HtmlNodeCollection links = htmlDoc.DocumentNode.SelectNodes("//a[@class='href1']");
var links3to5 = links.Cast<HtmlNode>().Skip(2).Take(3).ToList();
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