How to get the file right click menu in windows explorer in Java

Question

I am making a twin panel commander.

I made two JTables which displays the current directory contents. I would like to implement that a right click on a file would display the windows explorer shell context menu.

Is it somehow possible ?

Answer 1

Figured that out with using external app Runmenu .

    String runMenuApp = "path\\to\\runmenu.exe /show "; 
    String file = "\"" + "path\\to\\fileordir" + "\"";
    Process p = Runtime.getRuntime().exec(runMenuApp + file);