I want to write a sparql query to get rdf data based on their id. I am trying with
SELECT ?ID ?NAME WHERE {?ID = "something" }
but does not return the expecting results. Does anyone knows which is my mistake?
Actually rdf:id is the resource URI itself. You can utilise a SPARQL FILTER clause for filtering your result, or you can directly insert the URI in the WHERE clause of your query, eg
<myURI> ex:name ?name .
为了获得精确答案,您应该共享一小部分RDF数据(可能是Turtle格式,人性化)。
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