Javascript Regex and non-capturing parentheses
Question
I'm a bit rusty on my regexp and Javascript. I have the following string var:
var subject = "/admin.php?page=settings&tabs_added[114787535263592]=1&tabs_added[217770811582323]=1&tabs_added[198738186831542]=1"
I want to extract 114787535263592 , 217770811582323 and 198738186831542 .
I've tried to use non-capturing parenthesis (?:) :
var regexp = /(?:tabs_added[\[])(\d)+(?:[\]])/;
var pageid = regexp.exec(subject);
But the result I get ( ["tabs_added[114787535263592]", "2"] ) is not what I expected -- what am I doing wrong? Here's a jsFiddle: http://jsfiddle.net/KgpAw/
4 answers
solution1
5 ACCPTED 2012-03-29 14:38:52
You were very close. You need to capture the + as well. Otherwise you only capture one decimal digit:
var regexp = /(?:tabs_added[\[])(\
You should also make your regex global to find all matches:
var regexp = /(?:tabs_added[\[])(\d+)(?:[\]])/g;
Then you should loop through the results, you also don't need to have non-capturing groups because you're not using a quantifier on them ( ? , + , or * ), nor do you need to put your [ and ] inside a character class:
var regexp = /tabs_added\[(\d+)\]/g;
var result;
while(null != (result = regexp.exec(subject))){
document.write(result[1] + '<br />');
}
Note: It's better to use console.log for debugging purposes than document.write as long as you have a console available. (Chrome, Opera, IE9, and Firefox have consoles built in, and I think Safari does too, so you should have one available.) console.log provides much more valuable information when logging objects and arrays.
solution2
2 2012-03-29 14:42:53
You need global flag and match all digits: (\\d+) instead of (\\d)+ .
And don't need all those non-capturing subgroups.
var regexp = /tabs_added\[(\d+)\]/g;
var pageIds = [], match;
while(match = re.exec(str)) pageIds.push(match[1]);
pageIds;
solution3
1 2013-09-15 06:32:57
Hi i can solve above requirement in one line code.
<!DOCTYPE html>
<html>
<body>
<script>
var str="/admin.php?page=settings&tabs_added[114787535263592]=1&tabs_added[217770811582323]=1&tabs_added[198738186831542]=1";
var patt1=/\d{15}/g;
document.write(str.match(patt1));
</script>
</body>
</html>
solution4
0 2012-03-29 14:49:23
For multiple matches, you need to use the g modifier. Please try the following
var regexp = /(?:tabs_added[\[])(\d)+(?:[\]])/g;
var pageid = subject.match(regexp);
This will still contain the tabs_added part, but that can be removed separately
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