How do I use % character in NSString stringWithFormat

Question

How do I use the % character literal in an NSString stringWithFormat ?

I am trying to do: [NSString stringWithFormat:@"%%@,%@",string1,string2];

The first % does not show up.

Answer 1

[NSString stringWithFormat:@"%%%@,%@",string1,string2];

Answer 2

Two percent charicters, %%, will print as one %.

From the String Format Specifiers list.

Answer 3

试试这个：

   [NSString stringWithFormat:@"%@%%",str1];

Answer 4

Using % two times (as escape character) should give you what you need. An example printing %foo,bar would look like this

[NSString stringWithFormat:@"%%%@,%@", @"foo", @"bar"];