I am unable to understand the weird behavior of this program. I have 2 files, file1.c and file2.c
file.c is
#include <stdio.h>struct ll {
int key;
struct ll *next;
};
extern void func(struct ll*);
int main(void)
{
struct ll l = { 1, &l };
printf("%d %d\n",l.key,l.next->key);
func(&l);
return 0;
}
and file2.c is:
#include <stdio.h>
struct ll
{
struct ll *next;
int key;
};
void func(struct ll *l)
{
printf("%d \n",l->key);
printf("%d \n",l->next->key);
}
Now when I compile and run it, it shows segmentation fault. But where as in file2.c if I replace struct ll with :
struct ll
{
int key;
struct ll *next;
};
Then it works fine. I mean just by interchanging the order of the declaration, it is impacting the output.
The declaration of the struct should be the same both times, since struct is just a layout of data in memory, and you switch the variables.
in your case, the code in the function func
will try to dereference the integer 1
set in the main function. (or maybe do other weird things, as int and pointer are not compatible)
In file.c :
struct ll: [ int (key) | pointer (next) ]
struct ll l = { 1, &l }; // this causes:
l: [ 1 | &l ]
In file2.c :
struct ll: [ pointer (next) | int (key) ]
// so the passed struct is treated in the same way:
l: [ 1 | &l ]
next key
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.