I'd like to have an "explicit" servlet for a particular URL and a default(sort of a catch-all) servlet to handle all other URLs. So I created the web.xml file like this:
<servlet>
<servlet-name>My myindex.html servlet</servlet-name>
<servlet-class>in.shakir.web.MyIndexServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>My myindex.html servlet</servlet-name>
<url-pattern>/myindex.html</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>My all others servlet</servlet-name>
<servlet-class>in.shakir.web.MyHandlerServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>My all others servlet</servlet-name>
<url-pattern>*</url-pattern>
</servlet-mapping>
However it is not working(I get 404 error even for /myindex.html) I am using Tomcat 7.
But if I remove second (default or catch-all) part from my web.xml, then myindex.html works fine. So whats wrong with my url-pattern? Please advise.
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