how to get total items having date difference of more than 7

Question

I have to do a mysql statement to get total items having date difference of more than 7 from today (means today - 7)

This is my current statement:

SELECT 
    COUNT(*)
FROM 
    complaints 
WHERE 
    complaint_status = 'OPEN' AND 
    complaint_regdate <= curdate()
    complaint_regdate >= DATE_SUB(curdate(),INTERVAL 7 day)

I am getting this error:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'complaint_regdate >= DATE_SUB(curdate(),INTERVAL 7 day)' at line 1

Answer 1

You are missing an AND operator in your sql.

SELECT COUNT(*) FROM complaints WHERE complaint_status = 'OPEN' AND complaint_regdate <= curdate() AND complaint_regdate >= DATE_SUB(curdate(),INTERVAL 7 day)

Answer 2

You can use the BETWEEN operator for this

SELECT COUNT(*) 
FROM complaints 
WHERE complaint_status = 'OPEN' 
  AND complaint_regdate < (CURDATE() - INTERVAL 7 day)

Note you don't need the DATE_SUB function, you can just use a normal subtraction. Also these will only work if your complaint_regdate is a DATE column. If it's a DATETIME column you will need to use NOW() rather than CURDATE() or extract just the date pat of the field values.

Answer 3

It sounds like you're asking for the query to find the count where the date is more than 7 days in the past. Your current query listed above shows the count for everything within the last 7 days. So here is the query for more than 7 days past:

SELECT COUNT(*) FROM complaints WHERE complaint_status = 'OPEN' AND complaint_regdate < DATE_SUB(curdate(),INTERVAL 7 day)