assignment operator within function parameter C++

Question

I'm studying data structures (List, Stack, Queue), and this part of code is confusing me.

ListNode( const Object& theElement = Object(), ListNode * node = NULL);


template<class Object>
ListNode<Object>::ListNode( const Object& theElement, ListNode<Object> * node) {
    element = theElement;
    next = node;
}

1. Why there are assignment operators within function parameters?
2. What does Object() call do?

Answer 1

Those are not assignment operators. Those are default arguments for the function.

A function can have one or more default arguments , meaning that if, at the calling point, no argument is provided, the default is used.

void foo(int x = 10) { std::cout << x << std::endl; }

int main()
{
  foo(5); // will print 5
  foo(); // will print 10, because no argument was provided
}

In the example code you posted, the ListNode constructor has two parameters with default arguments. The first default argument is Object() , which simply calls the default constructor for Object . This means that if no Object instance is passed to the ListNode constructor, a default of Object() will be used, which just means a default-constructed Object .

See also:
Advantage of using default function parameter
Default value of function parameter

Answer 2

The assignments in declarations provide default values for optional parameters . Object() means a call to Object 's default constructor.

The effect of the default parameters is as follows: you can invoke ListNode constructor with zero, one, or two parameters. If you specify two parameter expressions, they are passed as usual. If you specify only one expression, its value is passed as the first parameter, and the second one is defaulted to NULL . If you pass no parameters, the first parameter is defaulted to an instance of Object created with its default constructor, and the second one is defaulted to NULL .

Answer 3

请访问http://www.errorless-c.in/2013/10/operators-and-expressions.html ，以获取使用C编程语言编写的运算符和表达式