ORDER BY breaking mysql query

Question

Someone on here helped put together this extremely useful query!

SELECT * FROM results r 
INNER JOIN categories c on r.id = c.result_id 
WHERE c.name in ('$purpose', '$prop_type', '$loan_type')
GROUP BY r.id
HAVING COUNT(c.c_id) = 3
LIMIT 50 OFFSET 0

Which is working great! However, when I try to order the results by using

SELECT * FROM results r 
INNER JOIN categories c on r.id = c.result_id 
WHERE c.name in ('$purpose', '$prop_type', '$loan_type')
ORDER BY r.usefulness DESC
GROUP BY r.id
HAVING COUNT(c.c_id) = 3
LIMIT 50 OFFSET 0

I get a syntax error. Am I missing something obvious here?

Thanks a lot!

Answer 1

there is an order for the parts of the query, and ORDER BY should be in the end (before the LIMIT and the OFFSET ... try this:

SELECT * FROM results r 
INNER JOIN categories c on r.id = c.result_id 
WHERE c.name in ('$purpose', '$prop_type', '$loan_type')
GROUP BY r.id
HAVING COUNT(c.c_id) = 3
ORDER BY usefulness DESC
LIMIT 50 OFFSET 0

also make sure that you have spaces in the end of any row...

notice that in mysql that is a shortened version for LIMIT x OFFSET y - you can just write LIMIT y,x

Answer 2

ORDER BY必须在HAVING之后进行。