I want to mock a method that returns a complex datatyp
class aClass
{
public:
virtual const QMap<QString, QString> aMethod() const;
}
class MockaClass : public aClass
{
public:
MOCK_CONST_METHOD0(aMethod, const QMap<QString, QString>());
}
This code does not compile: "macro "MOCK_CONST_METHOD0" passed 3 arguments, but takes just 2"
I think that the googlemock macro does not understand QMap and interpret the comma as parameter separator.
Is there a way to tell googlemock that QMap is the return value?
Just use a typedef
like this:
class aClass
{
public:
typedef const QMap<QString, QString> MyType;
virtual MyType aMethod() const;
}
class MockaClass : public aClass
{
public:
MOCK_CONST_METHOD0(aMethod, MyType());
}
You are right, the comma is interpreted as a parameter separator. You can define a preprocessor macro to protect the comma from being interpreted that way.
#define COMMA ,
MOCK_CONSTANT_METHOD0(aMethod, const QMap<QString COMMA QString>());
Please note, that this will not necessarily work for nested macro calls. For example, if MOCK_CONSTANT_METHOD0
would pass the second parameter to another macro, you would be in trouble again.
Just use ()
for complex param,
class MockaClass : public aClass
{
public:
MOCK_METHOD((const QMap<QString, QString>), aMethod, (), (const));
}
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