I'm newbie to xslt and i have below code which is not working for simple sort: help is appriciated.
<xsl:template match="ns0:MT_name">
<xsl:for-each select="name">
<xsl:sort select="name"/>
</xsl:for-each>
</xsl:template>
<?xml version="1.0" encoding="UTF-8"?>
<ns0:MT_name xmlns:ns0="http://example.com/sap/pi/TEST/xslt">
<name>11</name>
<name>88</name>
<name>55</name>
</ns0:MT_name>
<?xml version="1.0" encoding="UTF-8"?>
<ns0:MT_name xmlns:ns0="http://example.com/sap/pi/TEST/xslt">
<name>11</name>
<name>55</name>
<name>88</name>
</ns0:MT_name>
Change <xsl:sort select="name"/>
to <xsl:sort select="."/>
. The current context is already name
.
Try this XSLT 1.0 stylesheet:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://xyz.com/sap/pi/TEST/xslt">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ns0:MT_name">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select="name">
<xsl:sort select="." order="ascending"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
<xsl:sort select="." order="ascending"/>
so complete template is
<xsl:template match="ns0:MT_name">
<xsl:for-each select="name">
<xsl:sort select="." order="ascending"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:template>
I also notice in your example you have a ' mark
Your template doesn't create any output since the body of xsl:for-each
consists of xsl:sort
only. In order to generate the desired output, the stylesheet could look like this one:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://xyz.com/sap/pi/TEST/xslt">
<xsl:template match="ns0:MT_name">
<xsl:copy>
<xsl:for-each select="name">
<xsl:sort select="." data-type="number"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
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