This command returns my ip address with additional information.
dig @resolver1.opendns.com myip.opendns.com
; <<>> DiG 9.6-ESV-R4-P3 <<>> @resolver1.opendns.com myip.opendns.com
; (1 server found)
;; global options: +cmd
;; Got answer:
;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 48206
;; flags: qr rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 0
;; QUESTION SECTION:
;myip.opendns.com. IN A
;; ANSWER SECTION:
myip.opendns.com. 0 IN A 122.167.119.178
;; Query time: 199 msec
;; SERVER: 208.67.222.222#53(208.67.222.222)
;; WHEN: Fri May 18 11:46:51 2012
;; MSG SIZE rcvd: 50
I only want to extract my ip address from this. How can I extract my ip address from the dig
output?
Don't make this harder than it needs to be... use +short
[mpenning@Bucksnort ~]$ dig +short mike.homeunix.com
76.21.48.169
[mpenning@Bucksnort ~]$
If you are using bash shell this will work for you
grep -A1 "ANSWER SECTION" ip_file.txt | awk '{if(NF==5)print $5;}'
NOTE: My assumption is you are planning to extract the ip printed after the "ANSWER SECTION"
dig +short myip.opendns.com @resolver1.opendns.com
An alternative way is:
sudo apt install stuntman-client
then
myip=$(stunclient --localport 8888 stun.l.google.com 19302|grep Mapped|cut -d ":" -f 2|tr -d " ")
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